Acable capable of pulling 4,500 n snapped while trying to drag a 20,000 n compressor across the street. what is the coefficient of static friction for this scenario? note: the 4500 n cable is used as fs and is calculated the same as fk 0.225 > 0.225 4,500 n > 4,500 n 4.44 > 4.44 explain to me how you get your answer.

Explanation:

The cable snapped because the frictional force was greater than the tension in the rope:

Now,

where is the coefficient of static friction, and is the normal force. In our case, the normal force on the compressor is 20,000 N; therefore,

.

Putting this into the condition , we get:

it becomes positively charged by charging it