What is the vertex of the parabola? y+4=12(x−7)2

Vertex is (7,-4) for answer.

Hope this helps. :)

The answer to this question is (7,-4).
The parabola y+4=12(x−7)^2 can be moved so that the y term is isolated like so
                                    y = 12(x-7)^2 - 4
A parabola of the form y = a(x-h)^2 + k has its vertex at (h,k). So it follows that we take h = 7 and k = - 4.
The answer to this question is (7,-4).