Brainliest award will be given!with math ive been asking for hours! ! 1) solve the following equation by identifying all of its roots including all real and complex numbers. in your final answer, include the necessary steps and calculations. hint: use your knowledge of factoring polynomials. (x^2 + 1)(x^3 + 2x)(x^2 - 64) = 0 2) solve for the roots of x in each of the equations below. x^4 - 81 = 0 x^4 + 10x^2 + 25 = 0 x^4 - x^2 - 6 = 0 3) solve for the roots in the equation below. x^4 + 3x^2 - 4 = 0

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source