Angle ced is a right angle, ab congruent to cd, db bisects ac at e prove: quadrilateral abcd is a rhombus

Properties of Rhombus:
1) A flat shape with 4 equal straight sides. It looks like a kite or a diamond.
2) all sides have equal length
3) opposite sides are parallel and opposite angles are equal
4) the diagonals bisect each other at a right angle.
5) the altitude is the distance at right angles to two sides

∠CED is a right angle : GIVEN
AB congruent to CD : all sides have equal length
DB bisects AC at E : diagonals bisect each other at a right angle.

Ab=dc ac=de ad=bce i hope this !