An in-ground pond has the shape of a rectangular prism. the pond has a depth of 24 inches and a volume of 72,000 cubic inches. the length of the pond is two times its width. find the length and width of the pond to the nearest tenth.

Let
x> the length of the pond
y> the  width of the pond

we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24> 3000 in²

area of the base=x*y
3000=x*y> equation 1
x=2y> equation 2

substitute equation 2 in equation 1
3000=[2y]*y> 2y²=3000> y²=1500> y=38.7 in
x=2y> x=2*38.7> x=77.4 in

the answer is
the length of the pond is 77.4 in
the  width of the pond is 38.7 in

Hey, can you post the problem?