Aline has a slope of - 3/5. which ordered pairs could be points on a line that is perpendicular to this line? check all that apply. (–8, 8) and (2, 2) (–5, –1) and (0, 2) (–3, 6) and (6, –9) (–2, 1) and (3, –2) (0, 2) and (5, 5)

(–3, 6) and (6, –9) and  (0, 2) and (5, 5)

Step-by-step explanation:

Given : Slope = .

To find: Which ordered pairs could be points on a line that is perpendicular to this line.

Solution : We have given that  Slope = .

Slope = .

For (–8, 8) and (2, 2)

Slope = .

Slope = .

Slope = .

For (–5, –1) and (0, 2).

Slope = .

Slope = .

For, (–3, 6) and (6, –9)

Slope = .

Slope = .

Slope = .

For (–2, 1) and (3, –2)

Slope = .

Slope  = .

For (0, 2) and (5, 5)

Slope = .

Slope =  .

Therefore,  (–3, 6) and (6, –9) and  (0, 2) and (5, 5)

sorry not sure

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c