Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?

4 seconds

Let they meet after time 't' seconds

Let distance covered by puppy in 't' seconds be 'x' meters

So distance covered by kitten in 't' seconds is (180 - x ) meters

Time = Distance / Speed

so,

t = x / 25   for puppy

t = (180-x) / 20     for kitten

On solving,

x = 100 meters

t = 4 seconds

answer: was that a question or answer?

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3