Darren is finding the equation in the form y=mx+b for a trend line that passes through the points (2, 18) and (–3, 8). which value should he use as b in his equation?

Gradient = (8-18)/(-3-2)
= -10/-5
= 2

y = mx + b , at point ( -3,8 )
8 = 2(-3) + b
8 = - 6 + b
b = 14

we cannot simply take one of the y coordinate as value of b because b is the interception of straight line,not a point

Hello!

B - Y-intercept

First, let's write out the equation by finding the slope





Our slope is 2. Let's plug this in



Now let's find the y-intercept. Plug one of the x and y values into the equation. I'll use the ones for (2, 18) since they're positive.



He should use the number 14 as the y-intercept. Here's what his equation will look like.



Hope I helped! :3