Rachel says that graph r has a greater constant of variation that graph s. which statement explains whether rachel is correct?

For this case we have that by definition the constant of variation of a line is given by the slope m, of said line.

Where:

To find the slope of a line it is necessary to find two points through which the line passes.

To solve the given problem, we find the slopes of the lines shown in the graphics R and S:

Graphic R:

It is observed that the line passes through the following points:

Substituting in the formula of the slope we have:

Thus, the slope of the line of the graph R is given by:

Graphic S:

It is observed that the line passes through the following points:

Substituting in the formula of the slope we have:

Thus, the slope of the line of the graph R is given by:

then, the graph S has a variation constant greater than the graph R.

The graph S has a variation constant greater than the graph R.

Rachel's idea is wrong

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.