Consider the following geometric sequence -5,10,-20, if the reclusive formula for the sequence above is expressed in the form a^n = b*a^n-1 , determine the value of b

Hello from MrBillDoesMath!

  b = -2

Discussion:

Let's analyze this sequence.  

The first number = -5                               a(0)

The second number = 10 = -5 (-2)          a(1) = a(0) *-2

the third number  = -20 = 10 * (-2)          a(2) = a(1) * -2

The fourth number = -20 * (-2)                a(3) - a(2) * -2

In other words, the recursive (not reclusive) formula is

a(0) = -5         (this need to be stated! Not stated in the problem)

a(n) = a(n-1) * (-2)

This implies that "b" = -2.

Regards, MrB

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%