The net of a cube is shown on the coordinate plane. what is the surface area of the cube? a) 1 in2 b) 6 in2 c) 12 in2 d) 14 in2

The figure of this problem was not found, however, it can be solved and explained for didactic purposes.we know thatthe surface area of a cube=6*b²where b is the length side of a cubecase a) 1 in2sa=1 in²sa=6b²b=√(sa/> b=√(1/6) > b=√6/6 inif on the net the cube length is (√6/6) in, then the surface area will be 1 in²case  b) 6 in2sa=6 in²sa=6b²b=√(sa/> b=√(6/> 1 inif on the net the cube length is (1) in, then the surface area will be 6 in²case  c) 12 in2  sa=12 in²sa=6b²b=√(sa/> b=√(12/> √2  inif on the net the cube length is (√2) in, then the surface area will be 12 in²case  d) 14 in2  sa=14 in²sa=6b²b=√(sa/> b=√(14/> √(7/3)  inif on the net the cube length is (√(7/3) in, then the surface area will be 14 in²