Given a possible triangle abc with a=5,b=11,and a=23, find a possible value for

The question is as follow:

Given a possible triangle ABC with a=5, b=11, and A=23 degrees, find a possible value for angle B. Round to the nearest tenth.
A. 10.2° B. 11.2° C. 59.3° D. no solution
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a = 5   ,    b = 11   ,   and    ∠A = 23°

By applying the Law of Sines:




∴ sin B = 11* (sin 23°)/5 ≈ 0.8596

∴ ∠B = ≈ 59.3°

∴ The correct choice is option (C)
    C. 59.3°

(-14+3/2b) - (1+8/2b) = -5 -5/2b(-10+b) + (7b-5) = 8b-15(7/2b-3) - (8+6b) = -5/2b-11(5+2b) + (2b+3/2) = 4b+ 13/2