Ncircle a shown below, m arc bc is 61° and m arc ef is 76°: points b, c, e, f lie on circle a. lines be and cf pass through point d creating angle edf. measure of arc bc is 61 degrees and what is m∠fde?

The correct answer is 68.5°

The calculated result of the angle FDE is 68.5°. Whenever two chords cut across a circle, the resulting angle is equivalent to half of the sum of the measurements of the arc the angle intersects and that which the angle vertical to the first angle intercepts.

m<FDE = 1/2( Arc BC + Arc 76)

m<FDE = 1/2 (61° + 76°)

m<FDE = 137/2 = 68.5°

Give Brainliest if you please

it would be:

c.parallelogram.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.