Asap a rectangular garden has length three times as great as its width a second rectangular garden has the same width as the first garden and length that is 3 meters greater than the length of the first garden the second garden has area of 90 square meters what is the width of the two gardens?

5 meters

Step-by-step explanation:

First Rectangle :

Let the width = x

Given that length of the garden is 3 times that of width

Length = 3x

Second Rectangle:

As the width of both the rectangle is same

Width = x

Also given that the length of second rectangle is 3 meters more than that of first rectangle

Length = 3x+3 = 3(x+1)

Also given that Area = 90

Area = length * width

Hence either

x-5=0 or x=5

or

x+6=0 making x=-6 which is not possible as width can not be negative

Hence the width of the gardens is 5 meters

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!