You are getting a line-up ready for a school kickball game. you have 5 girls and 5 boys. the rules state each child must kick the same number of times and alternate girl-boy or boy-girl. how many ways can a line-up be made for one round of kicking?

There are 28,800 ways.

There are 10 possibilities for the first child, since it could be a boy first or a girl first.  After this, there are 5 possibilities for the second child (the other gender).  There are 4 choices for the 3rd child, 4 for the 4th child, 3 for the 5th child, 3 for the 6th child, 2 for the 7th child, 2 for the 8th child, 1 for the 9th child, and 1 for the 10th child:
10(5)(4)(4)(3)(3)(2)(2)(1)(1) = 28,800

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !