What are the real zeros of the function g(x) = x3 + 2x2 − x − 2? 1, –1, 2 1, –1, –2 1, –1 2, –2, 1

Zeros are x=-2, -1, 1

Step-by-step explanation:

We use grouping method

We group first two terms and last two terms

Factor out GCF from each group

FActor out x+2

To find out zeros , set g(x)=0

Now we set each factor =0 and solve for x

, x= -2

, take square root on both sides

x=1, x=-1

Zeros are x=-2, -1, 1

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.