Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of 2.6.

To answer the questions we use the z-table given.
a] The percentage of data items that lie below the z-score is given by:
P(z=2.6)=99.53
99.53%

b] The percentage of data items that lie above the z-score is given by:
1-P(z=2.6)
P(z=2.6)=0.9953
thus
1-P(z=2.6)
=1-0.9953
=0.0047
=0.47%

I’m confused as to what you are asking 66 2/3 percentage wise