What is the vertex of the parabola? y+1=−14(x−2)2 enter your answer in the boxes?

Vertex ( h,k) : ( 2 ,-1) .

Step-by-step explanation:

Given : y+1=−14(x−2)².

To find : What is the vertex of the parabola?

Solution : We have given that  y+1=−14(x−2)².

Vertex form of parabola: y=a(x−h)²+k.

Where , ( h ,k ) are vertex

we have y+1=−14(x−2)²

On subtracting by both sides

y = −14(x−2)² - 1

On comparing with Vertex form of parabola

a = - 14 ;  h = 2 ; k = -1.

Therefore, Vertex ( h,k) : ( 2 ,-1) .

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2