Step  1  : 1
Simplify —
3
Equation at the end of step  1  : 2 1 1 1
(—•((—•x)+12))-((—•((—•x)+14))-3) = 0
3 2 2 3
Step  2  :Rewriting the whole as an Equivalent Fraction :
 2.1   Adding a whole to a fractionÂ
Rewrite the whole as a fraction using  3  as the denominator :
14 14 • 3
14 = —— = ——————
1 3
Equivalent fraction :Â The fraction thus generated looks different but has the same value as the wholeÂ
Common denominator :Â The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
 2.2      Adding up the two equivalent fractionsÂ
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x + 14 • 3 x + 42
—————————— = ——————
3 3
Equation at the end of step  2  : 2 1 1 (x+42)
(—•((—•x)+12))-((—•——————)-3) = 0
3 2 2 3
Step  3  : 1
Simplify —
2
Equation at the end of step  3  : 2 1 1 (x+42)
(—•((—•x)+12))-((—•——————)-3) = 0
3 2 2 3
Step  4  :Equation at the end of step  4  : 2 1 (x+42)
(—•((—•x)+12))-(——————-3) = 0
3 2 6
Step  5  :Rewriting the whole as an Equivalent Fraction :
 5.1   Subtracting a whole from a fractionÂ
Rewrite the whole as a fraction using  6  as the denominator :
3 3 • 6
3 = — = —————
1 6
Adding fractions that have a common denominator :
 5.2      Adding up the two equivalent fractionsÂ
(x+42) - (3 • 6) x + 24
———————————————— = ——————
6 6
Equation at the end of step  5  : 2 1 (x+24)
(—•((—•x)+12))-—————— = 0
3 2 6
Step  6  : 1
Simplify —
2
Equation at the end of step  6  : 2 1 (x + 24)
(— • ((— • x) + 12)) - ———————— = 0
3 2 6
Step  7  :Rewriting the whole as an Equivalent Fraction :
 7.1   Adding a whole to a fractionÂ
Rewrite the whole as a fraction using  2  as the denominator :
12 12 • 2
12 = —— = ——————
1 2
Adding fractions that have a common denominator :
 7.2      Adding up the two equivalent fractionsÂ
x + 12 • 2 x + 24
—————————— = ——————
2 2
Equation at the end of step  7  : 2 (x + 24) (x + 24)
(— • ————————) - ———————— = 0
3 2 6
Step  8  : 2
Simplify —
3
Equation at the end of step  8  : 2 (x + 24) (x + 24)
(— • ————————) - ———————— = 0
3 2 6
Step  9  :Equation at the end of step  9  : (x + 24) (x + 24)
———————— - ———————— = 0
3 6
Step  10  :Calculating the Least Common Multiple :
 10.1   Find the Least Common MultipleÂ
     The left denominator is :       3Â
     The right denominator is :       6Â
        Number of times each prime factor
        appears in the factorization of: PrimeÂ
 Factor  LeftÂ
 Denominator  RightÂ
 Denominator  L.C.M = MaxÂ
 {Left,Right} 31112011 Product of allÂ
 Prime Factors 366
     Least Common Multiple:Â
      6Â
Calculating Multipliers :
 10.2   Calculate multipliers for the two fractionsÂ
   Denote the Least Common Multiple by  L.C.MÂ
   Denote the Left Multiplier by  Left_MÂ
   Denote the Right Multiplier by  Right_MÂ
   Denote the Left Deniminator by  L_DenoÂ
   Denote the Right Multiplier by  R_DenoÂ
   Left_M = L.C.M / L_Deno = 2
   Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
 10.3     Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3 are equivalent as well.Â
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. (x+24) • 2
—————————————————— = ——————————
L.C.M 6
R. Mult. • R. Num. (x+24)
—————————————————— = ——————
L.C.M 6
Adding fractions that have a common denominator :
 10.4      Adding up the two equivalent fractionsÂ
(x+24) • 2 - ((x+24)) x + 24
————————————————————— = ——————
6 6
Equation at the end of step  10  : x + 24
—————— = 0
6
Step  11  :When a fraction equals zero : 11.1   When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
x+24
———— • 6 = 0 • 6
6
Now, on the left hand side, the  6  cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
   x+24  = 0
Solving a Single Variable Equation :
 11.2      Solve  :    x+24 = 0Â
 Subtract  24 from both sides of the equation :Â
                      x = -24Â
One solution was found :Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â x = -24