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Mathematics, 23.07.2019 06:00 minersaysay22

Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 βˆ’ 3 = x square root of negative 2x plus 1 βˆ’ 3 + 3 = x + 3 square root of negative 2x plus 1 = x + 3 square root of negative 2x plus 1 βˆ’ 1 = x + 3 βˆ’ 1 square root of negative 2 x = x + 2 ( square root of negative 2 x )2 = (x βˆ’ 4)2 βˆ’2x = x2 βˆ’ 8x + 16 βˆ’2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 βˆ’ 2 = 0 βˆ’ 2 x + 8 βˆ’ 8 = 0 βˆ’ 8 x = βˆ’2 x = βˆ’8 both solutions are extraneous because they don't satisfy the original equation. what error did eloise make?

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Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 βˆ’ 3 = x s...
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