Write an equation of a line parallel to (-2,5) and (1,3) in slope intercept form the passes through the point (2,6)

First we have to find the slope of the first line. remember parallel lines have equal slopes.
slope is change in y over change in x so we have
(5-3)/(-2-1)=2/-3 so the line has slope -2/3.
we also know the point (2,6) is on the line. so we use point slope formula.
y-y1=m(x-x1) where m is slope and (x1,y1) is point on line
y-6=-2/3(x-2)

this is an equation of a line parallel to given points and passing through (2 6). you can put into slope intercept form by solving for y

Whats the question? theres not enough info