Afully inflated basketball holds .34 cubic feet of air. the basketball is overinflated to hold .64 cubic feet of air. what is the percent of changes for the volume of air inside the baskeball?

The percent of change can be calculated by finding the difference between the two volumes and then dividing by the original volume.

0.64 - 0.34 = 0.3

0.3/.34 = 0.882

This is approximately an 88.2% increase in volume.

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The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%