Given: ray bc bisects ∠abd and m∠dbe=80 find m∠abc.

I'm assuming "m∠dbe" is supposed to be m∠dbc because in my diagram of the angle, there is no point e.  if ray bc bisects (to divide into two equal parts) of the bigger  ∠abd, then m∠dbc is congruent to m∠abc. thus, m∠abc = 80°. 

Ddndnsjsjsjwhwhnsnana