(3−6n5−8n4)−(−6n4−3n−8n5) part 2 solve this quadratic equation. 4x2−2x−5=0

Part 1:
 We have the following expression:
 (3-6n5-8n4) - (- 6n4-3n-8n5)
 Rewriting we have:
 3-6n5-8n4 + 6n4 + 3n + 8n5
 Adding similar terms we have:
 2n5 - 2n4 + 3n + 3

 Part 2:
 We have the following equation:
 4x2-2x-5 = 0
 Using resolver we have to:
 x = (- b +/- root (b2 - 4ac)) / (2a)
 The solutions are:
 x1 = 1/4 - root (21) / 4
 x2 = 1/4 + root (21) / 4

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