If you roll two fair dice(one black die and one white die) in how many ways can you obtain a sum of at least 3

35

Step-by-step explanation:

When two fair dice are thrown , then the sample space would be :

(1,1), (1,2) , (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2) , (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2) , (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2) , (4,3), (4,4), (45), (4,6)

(5,1), (5,2) , (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2) , (6,3), (6,4), (6,5), (6,6)

The total outcomes = 36

We can see that the only outcome in the sample space has sum less than 3 =(1,1)

Now, the number of outcomes in the sample space having sum at-least 3 = 36-1=35

Hence, the number of ways to obtain a sum of at least 3 = 35

add the table and i will answer correctly

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°