20 ! the graph of y = ax2 + bx + c is a parabola that opens up and has a vertex at (-2, 5). what is the solution set of the related equation 0 = ax2 + bx + c? ø {-2} {5}

Hello,

y=a(x-h)^2+kvertex is (h,k)and when a is positive it opts up
svertex at -2,5
y=a(x+2)^2+5if we expand and set to zero0=ax²+4ax+4a+5dunnow how to solveI do know that A is positivealso since we gotvertex is (-2,5)it opens upthe vertex is the lowest point
the zeros are where y=0notice lowest point is (-2,5)5 is the lowest point5>0, so there are no zeroes
no solutions for that 2nd equation

The difference is 5,100m?