Events a, b, and c in a sample space have p(a)=0.2, p(b)=0.4, and p(c)=0.1. find p(a ∪ b ∪ c. if a and b are mutually exclusive, a and c are independent, and b and c are independent.

If and are mutually independent, then and .

If and are independent, then . Ditto for and .

The inclusion/exclusion principle says that



Since and are mutually exclusive, their intersection is the empty set. It then follows that also is the empty set, so the last probability is also 0.

Plug in what we know:

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40