Ineed with 2 alegbra questions. get 10 easy points!

For 5, we if the y-vlaues are increasing by a common ratio.

(y at x = 1) / (y at x = 0) is = 8 / 4 = 2
(y at x = 2) / (y at x = 1) is 24 / 8 = 3
(y at x = 3) / (y at x = 2) is 48/24 = 2

no, exponential function cannot model this data. you can see that the what you have to multiply to the previous changes.

exponential function has the form y = a(b)^x. if that "b" value kept changing, it's not exponential. like y = 4(2)^x would be exponential only for the first two values since y = 4(2)^x at x = 0 is 4 and y = 4(2)^x at x = 1 is 8, but it is not 24 at x = 2 since y = 4(2)^2 = 16.

6.

exponential function has the form y = a(b)^(x)
we see at x = 0, y = 1 so

1 = a(b)^0
1 = a(1)
a = 1

since a=1, we have y = 1(b)^x. to find b, use other points

since at x = 1 we have y = 3, then

3 = (b)^1
b = 3

so the function is y = 3^x