Asapwhich table shows the first four terms of the sequence described by : f(x)= 4(2)^x x f(x) 1 8 2 16 3 32 4 64 x f(x) 1 8 2 64 3 512 4 4069 x f(x) 1 4 2 8 3 16 4 32 x f(x) 1 4 2 6 3 8 4 10

We have the following function:
 f (x) = 4 (2) ^ x
 Evaluating we have:
 For x = 1
 f (1) = 4 (2) ^ 1 = 4 * 2 = 8
 For x = 2
 f (2) = 4 (2) ^ 2 = 4 * 4 = 16
 For x = 3
 f (3) = 4 (2) ^ 3 = 4 * 8 = 32
 For x = 4
 f (4) = 4 (2) ^ 4 = 4 * 2 = 64

 
 The correct table is:
 x    f(x)
 1    8
 2    16
 3    32
 4    64