Q4 q23.) solve the following exponential equation. express the solution set in terms of natural logarithms. then use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution.

Let z = e^(2x). Then your equation is
  z^2 +3z -28 = 0
  (z +7)(x -4) = 0
  z = -7 or 4

Taking the log of our definition of z, we have
  ln(z) = 2x
  x = ln(z)/2
So, the one real solution is
  x = ln(4)/2 = ln(√4)
  x = ln(2)
The decimal approximation is
  x ≈ 0.69

The slope of the function is 0.5.