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![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+5)^2=49\implies [x-\stackrel{h}{3}]^2+[y-\stackrel{k}{(-5)}]^2=\stackrel{r}{7^2}\qquad r=7](/tpl/images/0127/1575/20e79.png)
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Find the radius of (x-3)^2+(y+5)^2=49...
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