Mr. rifkin had 240 digital and manual cameras. after donating 82 digital cameras and 26 manual cameras, he had 3 times as many digital cameras as manual cameras left. how many digital cameras did he have first?

Let d = # digital cameraslet m = # manual camerasd + m = 240 equation 1(d-82) = 3(m-26) equation 2d - 82 = 3m - 78d - 3m = 82 - 78d - 3m = 16 equation 2 simplifiedwe have two equations with 2 unknowns: d + m = 240d - 3m = 16 subtract equation 1 from equation 2 -4m = -224 m = -224/-4 m = 56d + m = 240d = 240-md = 240-56d = 184he started with 184 digital cameras and 56 manual cameras

Ibelieve it would be letter c (: