Find f. f ''(x) = 7 + cos x, f(0) = −1, f(9π/2) = 0. f(

f ''(x) = 7 + cos x, f(0) = −1, f(9π/2) = 0.

To find f'(x) we integrate f''(x)

f'(x) = ∫ f''(x) = ∫ (7 + cos x) dx = 7x + sin x + A

To find f'x) we integrate f'(x)

f(x) = ∫ f'(x) = ∫ (7x + sin x + A) dx = 7* - cosx + Ax + B

Now we plug in the values and solve for A and B

f(x) = - cosx + Ax + B

f(0) = −1

f(0) = - cos(0) + A(0) + B

-1 = - cos(0) + B

-1 = -1 + B

B = 0

f(9π/2) = 0

f() = - cos()+ A() + B

f() = - cos()+ A() + B

0 = - 0+ A() + 0

A() =

multiply by on both sides

A =

So f(x) = - cosx + x + 0

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.