If the diameter of a nickel is 0.835in and the width of each nickel is 0.077in what is the approximate surface area of the roll of nickels? round to the nearest hundredth

We know that

[surface area]=2*[area of the base]+[perimeter of the base]*height
diameter of a nickel = 0.835 in 
r=0.835/2> 0.4175 in
area of the base=pi*r²> pi*(0.4175)²> 0.5473 in²
perimeter of the base=2*pi*r> 2*pi*0.4175> 2.6219 in

[surface area]=2*[0.5473]+[2.6219]*0.077> 1.2965 in²

the answer is
1.30 in²

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!