Arocket was launched into the air from a platform above the ground. the height, in feet, of the rocket above the ground t seconds after being thrown in the air can be determined by the expression -16t² + 64t + 80. what does the 80 in the expression represent?

The 80 is the height of the platform that the rocket is launched off of.

The general form of this function is

h(t) = -16t² + v₀t + h₀.

-16 represents the gravitational force.  v₀ is the initial velocity the rocket is launched with.  h₀ represents the initial height it is launched from.

The answer to your question is d 68%