Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. after adding b2 to both sides of the equation in step 4, what is the constant on the right side of the equation?   a.) -32b.) 112c.) 160

Please:  Use "^" to denote exponentiation:  2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2:             x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6.  Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

 x^2 + 4x +4  - 4 - 6 = 0.  Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10.  Take the sqrt of both sides:   x+2 = plus or minus sqrt(10).

Finally, solve for x:  x = -2 plus or minus sqrt(10).