Acolony of fruit flies exhibits exponential growth. suppose that 500 fruit flies are present. let p(t) denote the number of fruit flies t days later, and let k=.08 denote growth constant.

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 SEE ATTACHED IMAGE.

 Part A:
 The differential equation is:
 y '= 0.08y
 The initial condition is:
 P (0) = 500

 Part B:
 The formula for this case is:
 P (t) = 500exp (0.08 * t)

 Part C:
 After five days we have to evaluate t = 5 in the equation.
 We have then:
 P (5) = 500 * exp (0.08 * 5)
 P (5) = 745.9123488
 Rounding:
 P (5) = 746

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

Ithink the answer is: it is likely.