The stress distribution on a structure is given by s=2x^2+4x−30 where s is stress in pounds per square inch and x is the distance in feet from a reference point. at what distance is the stress equal to 0? f)6 ft g)3 ft h)12 ft j)5 ft

Step-by-step explanation:

Set the stress function s(x) = 2x^2 + 4x - 30 equal to zero and solve the resulting equation for x:

s(x) = 2x^2 + 4x - 30, or (after reduction), s(x)/2 = x^2 + 2x - 15 = 0.

Solve this by factoring:  (x - 5)(x + 3) = 0 yields x:  {-3, 5}

Assuming that x is positive (all distances are positive), x = 5

Answer j is correct:  x = 5 ft; at x = 5 ft, the stress will be zero at x = 5 ft.

its 4 because 2 times 2 is 4, if you double the number two you get four

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says