Awildlife refuge in south america has howler monkeys and spider monkeys. a biologist working there randomly selected eight adults of each type of monkey, weighted them, and recorded their weights in pounds. howler monkey: {15,16,17,17,17,17,18,19} spider monkey: {12,13,13,14,14,14,16,16} (a) calculate the mean and mad for each type of monkey. (b) calculate the means -to-mad ration for the two types of monkeys. (c) what inference can be made about the weight of both types of monkeys? explain.

Given:

howler monkey: {15, 16, 17, 17, 17, 17, 18, 19}

spider monkey: {12, 13, 13, 14, 14, 14, 16, 16}

The mean of the first set (howler monkey) = (15 + 16 + 17 + 17 + 17 +17 + 18 + 19)/ 8 

The sum of all weights is divided by the number of monkeys weighed (n = 8)

mean = 17

Do the same for the second set (spider monkey) = 12+ 13 + 13+ 14 + 14+ 14 +14 +16 + 16 / 8

mean = 15.75

The ratio of the two is 17:15.75 or 1.08 is to 1. 

y=x+9

?

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560