Use the distance formula d=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−− −−√ to find the length of the line with endpoints at (1,3) and (3,1)? question 2 options: 8√ 8 32−−√ 32 hide hint for question 2 question 3 (1 point) question 3 saved what is the slope of the line that is perpendicular to a line whose equeation is 3y = -4x + 2 ? question 3 options: 34 -34 43 -43

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.