∠aed is formed inside a circle by two intersecting chords. if minor arc bd = 70 and minor arc ca = 180, what is the measure of ∠ aed? a) 45° b) 50° c) 55° d) 60°

The complete question in the attached figure

we know that
The measure of the interior angle is the half-summit of the arcs that comprise it and its opposite.
so
∠ BED=(1/2)*[arc BD+arc CA]-------> (1/2)*[70+180]----> 125°
∠ BED=125°
∠ CEA=∠ BED-----> 125°
∠ AED=∠ CEB
so
2*∠ AED=360-125*2------> 2*∠ AED=110------>  ∠ AED=110/2----> 55°

the answer is
∠ AED= 55°