Arocket ship is two miles above sea level when it begins to climb at a constrast angle of 3.5° for the next 40 ground miles. about how far above sea level is a rocket ship after its climb? a. 2.4 mib. 4.4 mic. 653.9 mid. 655.9 mi

b). 4.4 miles

Step-by-step explanation:

Given :

Distance of the rocket above sea level = 2 miles

Angle of climb = 3.5°

Horizontal ground distance = 40 miles

Therefore, distance traveled by the rocket ship

tan θ = opposite / adjacent

tan 3.5 = BC / AB

tan 3.5 = x / 40

x = 40 x tan 3.5

x = 2.44 miles

Therefore, distance traveled by the rocket ship above the ground level after climb = 2 + 2.44

                 = 4.44 miles

450

step-by-step explanation:

you get texts and minutes, so why not

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!