Will mark the brainiest that is extra points aka full points what is the solution to the following system of equations? 2x−3y=−1 y=x−1

Hello!

We can solve this by using substitution

we can plug y = x - 1 into the other equation

So 2x - 3( x - 1) = -1

We can distribute the -3 to (x - 1)

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1

x = 4

We can plug x into the first equation

y = (4) - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!

2x-3(x-1)=-1. (Plug in equation for y into the first equation). 2x-3x+3=-1. -x=-4. x=4. y=x-1 y=4-1. Y=3. X=4.