Fis a differentiable function on the interval [0, 1] and g(x) = f(4x). the table below gives values of f '(x). what is the value of g '(0.1)?

The table is attached in the figure.

    g(x) = f(4x) ⇒⇒⇒ differentiating both sides with respect to x

∴  g'(x) = ⇒⇒⇒⇒⇒⇒ chain role

To find g '(0.1)

Substitute with x = 0.1

from table: 

f'(0.1) = 1 ⇒ from the table

∴  g'(0.1) = 4 * [ f'(0.1) ]  = 4 * 1 = 4

oof

step-by-step explanation:

just needed some points but try socratic