Suppose that you construct a histogram and a relative frequency histogram corresponding to a particular frequency table. identify one way the histograms will differ.

Step-by-step explanation:

Given that you construct a histogram and a relative frequency histogram corresponding to a particular frequency table.

Histogram is representing actual frequency for a class interval in numbers.

But relative histogram gives the ratio of actual frequency to the sum of frequencies.

Thus histogram gives actual while relative histogram gives ratio.

Histogram figures may be greater than 1, but relative histogram figures are always less than 1.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it