Acatapult launches a boulder with an upward velocity of 122 feet per second the height of the boulder h in feet after t seconds is given by the function h x 2 equals negative 16t ^ 2 + 122 t + 10 how long does it take the boulder to reach maximum height what is the boulders maximum height

It will reach about 242.56 feet after 3.81 seconds.

In this quadratic equations, we have the following values.
A = -16, B = 122 and C = 10

The expression for x-value of the vertex is (-b/2a). Doing this will give you the time of 3.8125 seconds.

Just input that value back into the equation and you will get the max height of 242.56 feet. 

2,4,5,8,10 are divisible by 40