Select the correct answer from each drop-down menu. in δabc, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively. m∠b = º, and m∠c = º. round off your answers to two decimal places.

The complete question in the attached figure

we have that
In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters

we can apply the Cosine Law to find the angles of the triangle.

find angle C
c²=a²+b²-2ab*cosC
cos C=(a²+b²-c²)/(2ab)-------->  cos C=(22.5²+18²-13.6²)/(2*22.5*18)
cos C=0.7967
C=arc cos (0.7967)-----------> C=37.19°

find angle B
b²=a²+c²-2ac*cosB
cos B=(a²+c²-b²)/(2ac)-------->  cos B=(22.5²+13.6²-18²)/(2*22.5*13.6)
cos B=0.60
B=arc cos (0.60)-----------> B=53.12°

the answer is
m∠B = 53.12º
m∠C = 37.19º