Is it possible for two numbers to have a difference of 8, and a sum of 1?

Let x be the first number and y be the second number. If a difference of these numbers is 8, then x-y=8. If a sum of these two numbers is 1, then x+y=1.

Solve the system of equations by adding two equations:

.

Hence y=1-x=1-4.5=-3.5.

the difference of 4.5 and -3.5 is 8 and the sum is 1.

It is possible the 2 numbers are - 3.5 and 4.5

let

the numbers be x and y

Two numbers to have a difference of 8 will be

sum of 1

combine the equation

x - y = 8

x + y = 1

2y = -7

y = -7 / 2

y = - 3.5

x + 3.5  =8

x = 8 - 3.5

x = 4.5

The numbers are 4.5 and -3.5

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region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true