Lamont builds a traingular shaped fence to hide his pool pump. he already has two sections of fencing measuring 8 and a half feet and 5 and a half feet which fencing length would lamont not be able to use as the third side of his fence?

Solve the equation using the given values: x= -2.5; y= -7.51. 2xy + 2x²

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

(x-5)1/2+5=2 what is a possible solution?