What is the slope of the line that is perpendicular to a line whose equation is 3y = -4x + 2 ? 3/4 -3/4 4/3 -4/3

First let's put 3y = -4x + 2 into slope-intercept form. That way we can figure out the slope easier. Remember that slope-intercept from is: y = mx + b, where m = the slope and b = y-intercept.

To change 3y = -4x + 2 into that form, all we have to do is divide both sides by 3 to get y alone:


Since the "m" in slope-intercept form is the slope of the equation, that means  is the slope of .

As a general rule to find a slope that is perpendicular, just find the negative inverse/reciprocal of your slope, meaning flip numerator and denominator of your slope and multiply by -1. Since your slope is , the negative inverse/reciprocal of your slope (aka the perpendicular slope) would be: .

The answer is A) 3/4.

Re-do the question and enter the picture